Question

As the population ages, there is increasing concern about accident-related injuries to the elderly. An artide reported on an experiment in which the medium lean engle-the farthe subject is able to lean and still recover in one step-was determined for both a sample of younger females (21-29 years) and a sample of older Pomale (67-8 years. The following observations are consistent with summary data given in the article: YF: 29, 34, 33, 27, 28, 32, 31, 36, 32, 27 OF: 19,14, 22, 13, 12 Does the data suggest that true average maximum lean angle for oider females (OF) is more than 10 degrees smaller than it is for younger females (YF)? State and to the relevant hypotheses at significance level 0.10. (Use for younger females and for older females.) Ho! Hu - 2 - 0 H:A-> H:Hs - 2 = 10 Hi-> 10 Mo: 1 - 2 = 0 HW - 20 O Holl - M2 10 Hi-W210 Calculate the test statistic and determine the value (Round your test statistic to two decimal places and your value to three decimal places.) Duvalue = State the conclusion in the problem context Fall to reject No. The data suggests that true average lean angle for older females is not more than 10 degrees smaller than that of younger females Fall to reject Mo The data suggests that true average lean angle for older females is more than 10 degrees smaller than that of younger females Reject Mo. The data suggests that true average lean angle for older females is more than 10 degrees smaller than that of younger female Reject Ho. The data suggests that true average lean angle for older females is not more than 10 degrees smaller than that of younger females

please i need help with problem
please show all the steps and round values according to it
thank you

Answer 1

Solution: Calculation table for data YE 야 29 co 34 14 33 22 [Y-x)2 |1-7)2 3비 9.31 4 4.41 31 182 16 % +1 12 4 27 13 어 29 12 도 80 32.. 3) 임이 36 2601 32 27 EE 300 121 15.21 849

Null hypothesis Ho: fujaratio Alternative hypother's Hilful ) 2 + 10 qz 0.10 Sampling variame sur le [ {p.) 4 EX-572] Z 84 g +74 10+5-2 n 158.9 13 '2 12:22 test -statist'e (t) = (1 - 821 - 10 4.9 49 1.915 12:22 S tr 2.59 P-value = 0.01124 P-Value 0.01

p-value is less than significance level. so, we accept the null hypothesis. We do not reject null hy for thesis so, obtion ② is correct answer.