Question

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0.0702 0.0702 incorrect incorrect At least one of the answers above is NOT correct. 1 of the questions remains unanswered. (1 point) A random sample of 100 observations from a population with standard deviation 8.31 yielded a sample mean of 91.5. Part 1: Part 2: - Part 3 Given that the null hypothesis is p = 90 and the alternative hypothesis is x 90 using a = .05, find the following: (a) Test statistic = 1.81 (b) P-value: 0.0702 Note: Round off the test statistic to 2 decimal places and the P-value to 4 decimal places.
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Answer 1

Son: Giuen, =100 68.31 = 91.5 - To test Ho el=go Us HI; +90 Test statistic; 3-il 11 91.5-90 8.31 / 100 1.5 N 11 0.831 Z - 1.8050 P-value: P [171> 1.817 0.0702. since P-value is greater than 0.05, We accept the nell hypothes is at 5% level of srgnificance il-go

La 2) 35, 0.02 = 99 sec : S228 sec To test. Ho ll= o see NS Hi;el to sec Test statistic 7 = X-el San 94-0 8 229 / 135 2.44 で p_value; P OZD 2.44) = 0.0141 Since Pivalue As lees than: 0.05, we reject the null hypothesis at O.C2 level of Srante cance