b. Since 5% of healthy people would exceed the minimum temperature for requiring further medical tests, find the z score with 100%−5%=95% of the total area under the standard normal curve to its left, rounding to two decimal places. While either technology or the standard normal distribution table can be used to find the z score, for the purposes of this problem, use technology.
a)
µ = 98.18
σ = 0.61
P ( X ≥ 100.6 ) = P( (X-µ)/σ ≥
(100.6-98.18) / 0.61)
= P(Z ≥ 3.97 ) = P( Z <
-3.967 ) = 0.000036
(answer)
= 0.0036 %
b)
µ= 98.18
σ = 0.61
P(X≤x) = 0.95
z value at 0.95= 1.6449 (excel formula
=NORMSINV(0.95))
z=(x-µ)/σ
so, X=zσ+µ= 1.645 *0.61+98.18
X = 99.183
(answer)
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