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A random sample of college students was asked to respond to a survey about how they spend their free time on weekends. One qu

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Answer #1

solution:- option C. 0.23

explanation:-

given the above information on the table

total cases = 200

total favorable outside employment = 46

if one student is randomly chosen from the group , the probability that the student chose "outside employment" as their most likely activity on a saturday morning

=> favorable of outside employment/total cases

=> 46/200

=> 0.23


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