Question

Question 15 (1 point) Three males with an X-linked genetic disorder have one child each. The random variable X is the number of children among the three who inherits the X-linked genetic disorder. The probability distribution for random variable X is given below X P(X=x) O 0.4219 0.4219 0.1406 N 3 0.0156 Determine whether this table satisfy all the requirements for probability distribution It does not satisfy all requirement It satisfy all requirement It satisfy some requirements but not all o e 8

Answer 1

probability distribution of random variable x has two conditions Each probability PC ze) must be between o and Os p() 2) The sum of all the possible probabilities is PC) -1 Х PCX =2) 0.4219 0.4219 0.1406 2 0.0156 3 Total 1-{P(2) and I Here and all P(x1=x) is between (PCX 1= x)) = 1 This table satisfy all requirement for probability distribution It satisfy all requirement.