Question

Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poil asked respondents if they felt vulnerable to identity theft. In the poll, n=990 and x = 599 who said "yes." Use a 90% confidence level. Click the icon to view a table of z scores a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. (Round to three decimal places as needed.) c) Construct the confidence interval. (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. O A. There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound. OB. 90% of sample proportions will fall between the lower bound and the upper bound. OC. One has 90% confidence that the sample proportion is equal to the population proportion OD. One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.

Answer 1

let, Number of respondents they felt vulnerable to identify toneff, out theft out of n= 990 Here, 599 na 990, x= we have, - 599 0.6059 n ggo 0.39 49 Q : = 1- 0.6051 = The point of the population proportion p Ansi- P = 0.605 error (6) Here, we have to find the value of the margin of E: we know that too (12) %. GI for population proportion (p) is, 9 2 (Å - Zaland & Åt Zala where, margin of erruny E= Zatz & given that significance level (&) - ool (10% (10% Idle = 2011 1.645 E = 1.645 0.60SX 0.395 990

RE=00026 c): The gool o I for population proportion (p) is (0.6os + 1.645 o for x 0.395 ggo (0.580, 0.631 ) o o 580 <p <[0.631 a Anso- Interpretation 8 A There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound,