Since the coefficient of dy/dx is non constant. It means it is non linear differential equation.
Also, its higher derivative is second order.
So the correct answer is Not linear; order:2.
option b is correct.
State the order of the following ordinary differential equations and classify them as linear or non-linear. (2t-e2t) day +64 dy dt4 dt = - ye-66 + 2sin(5t) The order of the differential equation is and it is ---Select--- d²f dp2 = pln(-6p) + 2e5p The order of the differential equation is and it is ---Select--- day sinh( ) – In(6) dy dx = 2cos(5y) – y dx2 The order of the differential equation is and it is ---Select---
Consider the equation 2xy (y dx + x dy) = (y dx - xdy) sin - Is the equation exact? If not, find an integrating factor, and solve the equation that is exact with the integrating factor
[2xy cos (x+y) – sin x) dx + x2 cos (x+y) dy o
Determine whether the differential equation is linear or
nonlinear
Problems For Problems 1-6, determine whether the differential equa- tion is linear or nonlinear. d3 y day +4 2. dy + sin x dx = xy2 + + tan x dx3 dx2 COS X. 1 6. Vxy" + '++. In x = 3x3.
Evaluate the integral 1 ET sin(2²) dx dy by reversing the order of integration. With order reversed, 6 sin(x²) dy dx, where a = ,b= C= and d Evaluating the integral, So S, sin(x2) dx dy =
The general solution of the first order non-homogeneous linear differential dy equation with variable coefficients (x + 1) + xy=e, I > -1 equals dx Oy=e-* [C(x2 - 1) + 1], where is an arbitrary constant. None of them Oy=e* [C(x2 – 1) +1], where is an arbitrary constant. yre *(C(x + 1) - 1], where is an arbitrary constant. Oy=e" (C(x - 1) + 1], where is an arbitrary constant.
15. (2xy + y^2 ) dx + (2xy + x^2 − 2x 2y^2 − 2xy^3 ) dy = 0
Question 2 3 pts The general solution of the first order non-homogeneous linear differential dy equation with variable coefficients (x + 1) + xy = e-, x>-1 dx equals y=e-* (C(x + 1) - 1], where C is an arbitrary constant. Oy=e" (C(x - 1) + 1], where is an arbitrary constant. Oy=e" (C(x2 – 1) + 1], where C is an arbitrary constant. None of them O y=e" (C(x2 – 1) +1], where C is an arbitrary constant.
1a) Find dy/dx x = te', y = t + sin t b) Find dy/dx and d’y/dx2 for which t is curve concave upward x = x3 + 1, y = t - c)Find the points on the curve where the tangent is horizontal or vertical. Draw the graph x = 13 – 3t, y = t3 – 312 d) Find the area enclosed by the x-axis and the curve x = t3 + 1, y = 2t – t?....
solve the given de or ivp
3. [2xy cos (x²y) - sin x) dx + rcos (2²y) dy = 0.