6. (20 pts) A random variable X has a binomial B(100,0.2) distribution A. Explain why it...

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Question

Answer 1

Answer #1

6)A) n = 100

p = 0.2

np = 100 * 0.2 = 20

nq = n(1 - p) = 100 * (1 - 0.2) = 80

Since np > 5 and nq > 5, so we can use normal approximation to the binomial distribution .

$\mu$ = np = 100 * 0.2 = 20

$\sigma$ = sqrt(np(1 - p))

= sqrt(100 * 0.2 * (1 - 0.2))

= 4

Answer 2

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