Solution:-
Given that,
mean = = 268
standard deviation = = 15
Using standard normal table,
P(Z < z) = 4%
= P(Z < -1.75 ) = 0.04
z = -1.75
Using z-score formula,
x = z * +
x = -1.75 * 15 + 268
x = 241.73
x = 241 days.
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard...
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The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability...
not sure about this one any help would be appreciated! The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b If the length of pregnancy is in the lowest 4%, then the baby is premature Find the length that separates premature babies from those who are not premature a. The probability that a pregnancy will last 309...
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