Solution:
n= 453,p= 9%=0.09
μp^ = p = 0.09
σp^ =✓ {[p( 1-p)]/n}
= ✓{ [0.09 ( 1-0.09)]/453}
= 0.0134
P( p^ >0.11) =1-P( p^ <=0.11)
=1- P{[ (p^ -μp^) /σp^ ]<=[(0.11 - 0.09)/0.0134]}
=1- P (Z <=1.49)
=1- 0.9319
0.0681
Correct A film distribution manager calculates that of the films released are flops if the manager...
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