Question

The impurity level (in ppm) is routinely measured in an intermediate chemical product

Question 2 of 3 -/1 E View Policies Current Attempt in Progress Please use the accompanying Excel data set or accompanying Text file data set when completing the following exercise. The impurity level in ppm) is routinely measured in an intermediate chemical product. The following data were observed in a recent a test 24,2.5, 1.7, 1.6,1.9, 2.6, 1.3, 1.9 2.0, 25, 26, 2,3,2,0,1.8, 1.3, 1.7,20,1.9, 2.3, 1.9, 24.1.6 Can you claim that the median impurity level is less than 2.5 ppm? State and test the appropriate hypotheses using the sign test with Q0.05. What is the P-value for this test? Calculate the observed number of plus differences.ro Calculate the value using the binomial distribution and round your answer to four decimal places de 98.7654). P-value HO:2.5 versus H11025. Conclusion Reject nullypothesis Statistical Tables and Charts e Textbook and Media Save for Later Attempts: 0 of 3 used Submit Answer

Answer 1

Given that claim: H.: u = 2.5, H :<2.5 1 xi Nm 4 5 6 7 2.4 2.5 1.7 1.6 1.9 2.6 1.3 1.9 2 2.5 2.6 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 xi-2.5 -0.1 0 -0.8 -0.9 -0.6 0.1 -1.2 -0.6 -0.5 0 0.1 -0.2 -0.5 -0.7 -1.2 -0.8 -0.5 -0.6 -0.2 -0.6 -0.1 -0.9 2.3 2 1.8 1.3 1.7 2 1.9 2.3 1.9 2.4 1.6

a) Now we have to find the observed number of plus differences(r+). observed number of plus differences = pt = 2 irt = 2

b) Now we have to find the p-value. X follows binomial distribution with n = 22 and p = 0.5. p-value = P(X srt) = P(X s 2). Using excel formula: =BINOM.DIST(2,22,0.5,TRUE) we got P(X < 2) = 0.945. p-value = P(X < 2) = 0.0001. .. p-value = 0.0001

c) Now we have to write the conclusion. Given that the significance level a = 0.05. If p-value is less than significance level a, reject Ho. In our problem, p = 0.0001 <0.05. = Reject H. Conclusion: :: Reject null hypothesis.

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