Question

Question 2 of 3 (1 point) View problem in a pop-up 11.1 Section Exercise 8 (calc) Action % of time 70.8 8.2 9.0 12.0 On time National Aviation System delay Aircraft arriving late Other (because of weather and other conditions) Download data Source: www.transtats.bts.gov Records of 200 flights for a major airline company showed that 128 planes were on time; 32 were delayed because of weather, 16 because of a National Aviation System delay, and the rest because of arriving late. Ata -0.10, do these results differ from the government's statistics? Use a graphing calculator Part 1 out of 4 Identify the claim with the correct hypothesis. Ho: On-time performance by airlines is distributed as follows: 70.8% on time, 8.2% National Aviation System delay, 9.0% aircraft arriving late, and 12.0% other. (select) H]: The distribution is not the same as stated in the null hypothesis. (select)

Answer 1

Here we will conduct chi square goodness of fit test

The claim is the null hypothesis

E F G H K Total 200 Expected value = given proportion * 200 Other 32 24 2.666666667 5.982637 chi square Σ (0-E2 E A B C D Action On time National Aviation Sys. Delay Aircraft arriving late 2 Observed 128 16 24 3 Expected 141.60 16.40 18.00 4 Chi square contribution 1.306214689 0.009756098 2 5 6 Chi square statistic = 5.9826 SUM(B4:14) 7 number of category(gates) 4 8 degree of freedom = 9 Significance level 0.1 10 P value 0.1125 11 12 The p-value is greater than the significance level, hence we fail to reject the null hypothesis. O = Observed frequency E= Expected frequency 3 B7-1 CHISQ.DIST.RT(B6,B8)

We have no evidence to say that the on time performance by aircrft is distriibuted differently then in the null hypothesis.