TRUE
Inflection point is a point where concavity of the graph changes.
It can be obtained by putting second derivative equal to zero. And in some cases or function which are having different domains at different steps.
Question 8 4 pts At an inflection point for a function f, the second derivative is...
QUESTION 18 Suppose you calculate the second derivative of a function to be f(x)-14x-91 and that one critical point? of the critical points is 13. Using the second derivative test, what can you say about the origin al function, f(x), at this O The function has a maximum at 13. The function is increasing for all x < 13. The function has an inflection point at x = 13. O The function has a minimum at 13 O The function...
Question 2-Part B: How many inflection points for the function whose second derivative is f"(x) sin(3x)-cos(x2) for 0 < x < 3 Question 2-Part B: How many inflection points for the function whose second derivative is f"(x) sin(3x)-cos(x2) for 0
What does the Second Derivative Test guarantee about the point x=2 of the function f(x) = .0001(x - 2)4? The point x=2 is a local maximum The point x=2 is a local minimum. The point x=2 is an inflection point. The point x=2 is not a critical point. The Second Derivative Test does not apply to x=2.
Find the critical point of the function. Then use the second derivative test to classify the nature of this point, if possible. (If an answer does not exist, enter DNE.) f(x, y) = x2 − 4xy + 2y2 + 4x + 8y + 8 critical point (x, y)= classification ---Select--- :relative maximum, relative minimum ,saddle point, inconclusive ,no critical points Finally, determine the relative extrema of the function. (If an answer does not exist, enter DNE.) relative minimum value= relative...
A function and its graph are given. Use the second derivative to determine each of the following. Check your results against the graph shown. f(x) = x3 - 6x2 + 5x + 6 f(x -6 -4 -2 LLLLL X 416 Determine the interval on which the function is concave up. (Enter your answer using interval notation.) Determine the interval on which the function is concave down. (Enter your answer using interval notation.) Locate the point of inflection. (If an answer...
Question 11 10 pts The derivative f'(2) of an unknown function f(x) has been determined as f'(x) = (x - 2)(+3)2. Use this derivative to find the intervals where the original function f is increasing/decreasing. Then find the x-values that correspond to any relative maximums or relative minimums of the original unknown function f(x). O no relative maximum; relative minimum at x=2 relative maximum at x=-3; no relative minimum O relative maximum at x=2; relative minimum at x=-3 relative maximum...
17. Given the following function and its first and second derivative: 20-2 6-43 f'(x)= f"(x) = [2 pts] 1) Find the horizontal and vertical asymptotes of f(x), if any. f(x)=x-2x=1 نر [2 pts) ii) Find all critical numbers. Note: NOT a point, just critical numbers only. [5 pts) iii) Find the intervals of increasing and decreasing then finding all local maximum minimum values. [5 pts] Find the intervals of concave upward and concave downward. [2 pts) Find inflection point, if...
Question 5 4 pts Find the second derivative of the given functions: f(x) = 8x3.9x2 + 6x +4 (a) 48 (b) 48x2 + 18 (c) 48x2-18x (d) 48x - 18 (e) 48x + 18 O (a) O (b) O (c) O (d) O (e)
2. (20 pts) Consider the following function with its second derivative in simplified form (you should compute the first derivative): 4.2 f(x) = x²+1 f"(x) = 8.2(x - 3)(x + 3) (x² + 13 "None" could be an appropriate answer for some of the statements below: (a) (2 pts) The domain of f(x) is (b) (2 pts) An x-intercept of the graph of y = f(x) occurs at x = (c) (2 pts) The graph of y = f(x) has...
Question 10 4 pts Find the second derivative for the sales function: S(x) = 800x1.2 (a)960x 0.8 (b) 800x-0.8 (c) 192x-0.8 (d)192x+0.8 (e) 192 O (a) O (b) (c) (d) (e)