Given 9 speices are there in which he have to select 3 where order is important
No. of ways of selecting 1st speice =9
No.of ways of selecting 2nd speice =8 ways ( because one speice is already selected)
No. of ways of selecting 3rd speice = 7 ways( because 2 pieces already selected)
Total no. of ways of slect all 3 spieces = 9*8*7=504 ways
This can directly answered by using permutations because 3 to be selected from 9 where order is important
No. of permutations= 9P3=(9!/6!)= 9*8*7=504 ways
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