Question

Suppose you first received a shipment of six televisions. Four of the televisione are detective Itwa televisions are randomly selected compute the probably that both televisions work. What is the probability at least one of the two television does not work? The probability that both televisions work is Round to three decimal places as needed The probability that at least one of the two televisions does not work is (Round to three decimal places as needed) Enter your answer in each of the answer boxes O e to sech

Answer 1

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solution Given data, Total number of television = 6 Number of defective television - 4 number of working television = 2 Number of randomly selected television = 2 (9 202 P (Both televtsion work) = 6Cq favourable outcomes Total outcomes =0.06666 x 0.067 - 15 15 1 IP (Both television work) -0.067 15 = P(At least one of the two television work) = 1 - P(Both televiste wak IS 0.9333 0.933 15 14 15 0.933 P( At least one of the two television work)