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Consider the following Ordinary Differential Equation (ODE): dy = 0.3 * x2 + 0.04 * 26 – 4* y? dx with initial condition at p

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Answer #1

dy da 0.3x2 + 0.04 26- 4 y2 U at Io = 0.6875, 9. = 0.0325 The Runge - Kutta Method of the second order is Yits = Y; + 1/ (kgiFor i = 1 : X2 = Xqth = 0.8125 + 0.125 X2 = 0.9375 2 kjs = 0.3%,? + 0.04 26 - 4y, = 0.3 (0.8125)2 +0.04 (0.81251 - 4 (0.0538)ka, = 0.34 2 С Уз = 9, + 3 (k+2 + K22) - О.08 28 + 3 (о. 2634 + 0.34 26 ) (О. 12 5) 9; - О. 1207 For j= 3 х4 = х3 +ь - 1.06 2

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