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Score: 0 of 1 pt 4 of 18 (1 complete) HW Score: 5.56%, 1 of 18 pts 5.4.32 8 Question Help The mean height of women Assume o =

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Answer #1

Solution :

Given that ,

mean = \mu = 64.2

standard deviation = \sigma = 2.73

\sigmaT = \sigma / \sqrt n = 2.73 / \sqrt 75 = 0.3152

P(T > 65) = 1 - P(T < 65)

= 1 - P[(T - \mu T ) / \sigma T < (65 - 64.2) / 0.3152]

= 1 - P(z < 2.54)

= 1 - 0.9945

0.0055

The probability that the mean height for the sample mean greater than 65 is 0.0055

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