Solution :
Given that ,
mean = = 64.2
standard deviation = = 2.73
= / n = 2.73 / 75 = 0.3152
P( > 65) = 1 - P( < 65)
= 1 - P[( - ) / < (65 - 64.2) / 0.3152]
= 1 - P(z < 2.54)
= 1 - 0.9945
0.0055
The probability that the mean height for the sample mean greater than 65 is 0.0055
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