Question

M Review Constants Part A - Determine the equivalent inductance to the right of terminals b and e, including L4 Learning Goal: To reduce series-parallel combinations of inductors or capacitors to an equivalent inductance or capacitance. Inductors in series and parallel combine like resistors in series and parallel. It is possible to use Kirchhoffs current law to find the current through the equivalent inductance. Moreover, capacitors in series combine like resistors in parallel and vice versa. It is possible to use Kirchhoffs voltage law to find the voltage across the equivalent capacitance For the network in Figure 1(Figure 1), determine the equivalent inductance to the right of terminals b and e, including L4. Assume that is = 9.0 mA, 16 = 1.0 mA, 17 = 3.0 mA, L1 = 4.0 mH , L2 = 9.0 mH , L3 = 10.0 mH , L4 = 2.0 mH , L6 = 10.0 mH , LB = 6.0 mH L7 = 10.0 mll , and Ly = 6.0 mll Express the equivalent inductance, LB, in millihenries to three significant figures. View Available Hint(s) Atvec ? L- MII Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining Part B - Determine the equivalent inductance to the right of terminals a and d For the network in Figure 1(Figure 1), determine the equivalent inductance to the right of terminals a and d. Assume that is = 8.0 mA, 16 = 6.0 mA, 17 = 3.0 mA, L1 = 7.0 mH , L2 = 7.0 mH , L3 = 9.0 mH , L4 = 3.0 mH , Ls = 6.0 mH , LA = 4.0 mH , L7 = 6.0 mH , and L = 3.0 mH Express your answer in millihenries to three significant figures. View Available Hint(s) IVO AED Ivec ? Lad mH Submit Figure < 1 of 4 Part C - Determine the equivalent capacitance to the left of terminal a, including C4 L b ac For the network in Figure 2(Figure 2), determine the equivalent capacitance to the left of terminal a, including Cd. Assume that vi = 1.0 V, 09 = 9.0 V, 03 = 1.0 V, 05 = 10.0 V , V6 = 9.0 V, C1 = 10.04F, C2 = 3.0 pF, C3 = 2.04F, C4 = 7.0 AF, C; = 4.0 pF, C6 = 6.0 uF. C7 - 1.0 MF, and Cy = 2.0 F. Express the equivalent capacitance, Co, in microfarads to three significant figures. LA 3L View Available Hint(s) L Lg VO Ako vec ? Figure 1

Answer 1

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figure 1: LI le b sro ( diy Ly3 mm LE 4. li L7 e En AS Equivalent Indulance to the right of terminals ble Ly= lomt, L=6with L2=9m, Ly=20k La= lould, ami 0 b Lg = = (my qu Am 3lom 3 12m 2m. binti เรา b Town 2) 2u Bunun Jenis omi Libe parallel 10 fm tom = 12mm com/firm co *12" lotla 3 & senis sutus bo wilt? P7 Пси 5:4595 ml -> bo Lereo 3 18-4545ml 2 a Lbe 3:454.357 qm ehe 145mA paralla a) Libe = 2m /19.4545 Lbe : 2m*14.4541m ant 14 urusm 1.7569 mH the = 1:78890H indructance equivaled LB = Ilbea 1.7569 will B 4 !. Equivalul Euclulance to the right of 4=7m44, .4 I. Imith L3=91H, L4 = 3mu Lyzont, Lumu, by = SMH, Lp=3MH 2 am Emil 7m mm 7m yoma sum و بها mam am 33m ๆ หา mm 3m ofon fun mom Benin 4+3= full Ladd 6m 6m/17m 1412 5 23.2308mi 687 66)

u > am senin my § 3m & 3.2.300 m 10-230fm am bun parallel lad Gm lad Im +3.2387 m = 10:2387m 3*10.23670 3to: 138pm 2.3198 mh 51 fm b) fm mo name 2-3198m &am& 8-1198mH 6m a series Lad lad parallel om 42.3198m = 8:3198 mit que * 8.3198 m (am +8.3198m) I 4-3233 mA ym m q senin 4.3233m Im +4.3232 m Lad MH 11:32 33 z Lad Lada 11.3232 mts - of 'Equivalul Capacitance including cu to left of terminal a Circuit C2 HL tu leftog terminal cu Î Cg C7 cy e Sassume) Calouf ( 2 uf Cq. - Fuf loluf Series a lour & auf are in senin 2AF qui a fall fru عمر ما = 1.66 Auf lolutul 12 "

10 qurd 1.6880 f are in parallel ch 7.up = parallel Caca Cae 74 fl66du 8-66fur Caza 8.68 tuf Equivalent Epacitance Re: Equivalent Capacitance to the right of terminal bi Pralucing G & cal Circuit will be suf CEE SUF, (G=Euf cs = tour D 11 o b G (1 74 11 1 senin C I g senin 64 I Сі su Su Ć 4- csc 1021 5H & Gliare in sonia 576ur sulloll are insing Jo u 2.72734 13MP 3:33 uf نر ( 56) li stel (5+12) H 3 1. 720417 33333 421 be 2.71273 +3.333 = 6.0606 uf Chen . B Cha 6061 MF ES Equivalent capacitance across terminals abe (za ruf, Cyclouf (i=7uf, a6uf, C;= luf, (6=6uF , 67=6uf, G=lour 7 Inn 641 0 64, lou senia bu TUF loll I serien I senin *در ه) مه ) - مر له عی) = 3.75uA لان : Gu jue IMF Que are in Senin (186) 4 o.fratur (tolu surd auf are in series 6 u Xan 3.2307 uf (otolu

2) ви -11 [ои 3.2 Зо) и р ميرز .3 in parallel 3- дедҢ (од Toast 13. 236 } ще paroles 3) paralel ogstui & Bar ufare in Paraller 6. Уt + 2 x ) и — R ur (и гч боде 19ърди ч. в ден (0) 11-130 ) е 44 46 24. оло ?n senin 13.30) де Senin 1 |3 - 2 342 Ч: Кении 13. - 34} +46 сә1) и г 1 (д ( э 3. чі 수 би parallel € 3-4 эгнve in p v«л 3-42 А ". Соль — (6 €3. Ч. 1)А (Cab О. Чt Эрд? С ч ao ві, 4 3 часа и, 4 = 3 И, 2 2.мн, С1: 7ми. о t... <a h. Liga 6mli ==2mA, ? = 7mat, irzloud = ? = ou ? d 3 Ү, Apply kee but node ③ 1 + Pariy-is 1, EQ - - с Apply ledlat much @ -7 м-tow ~17mA (2 + + ? = 0 2 - 13 - 12 = foru)- 11 m = zarama 7 . 2-t Tu (Parisma

Apply kul in loo p © a 6 G) ce V,= BV, V3 = V -u 2 ovi C6 I tub V2 V V6=1 =? V4 ut V3 = 3+1 - Votup ty Apply k vlin loup ☺ = 40 -Vu tuz - Vgrave za Vab V2 = Uutustu 4+2+1 - 7U Vab=7V .-74