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Combinatorial proof for 4^n = 2^n * 2^n (show both sides count the same thing)

Combinatorial proof for 4^n = 2^n * 2^n (show both sides count the same thing)

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Answer #1

Parros A 22 prove by principal of mathematical Induction we going to step. Let n=1 2.H.S= 4. Ronis = 2:2 =4= L.H.S. at is t

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