1. (10 points) Find the inverse Laplace() = C'{F} of the following: 4 6 1 a)...
help 1. (10 points) Find the inverse Laplace f(t) = --'{F} of the following: 4 6 1 a) 2 F(s) + S 8 +8 S b) 2 F(s) c) 2 F(8) (8 - 1)(8-2) 8 +3 $2 + 2s +5 7s2 + 23s + 30 (8-2)(82 +2s + 5) d) F(s)
(1 point) Find the inverse Laplace transform f(t) = C-' {F(s)} of the function F(s) = 2s - 3 32 + 16 560) = c { 2s - 3 32 + 16 = 2cos(4t)-2 sin(4) help (formulas)
1. (10 points) Find the inverse Laplace transform of the following: 85 - 4s +12 s? +45-5 b. F(x) = s(s? +2s + 5) 2. (10 points) Determine if the following differential equation is exact. Be sure give a reason for why or why not. If it is exact, solve it. (xy? + 3x y)+(x° +xºy)y'=0 a. F(s)= (1-25)e-
Find the inverse Laplace transformation of: a) F(s)- b) F,(s)--2 c) F(s) = 2,242 4 s2+6s +5 s2 +3s +1 3+2s+s s2 +9s +18 e) F(s)--一5 2s4 +12s+90 (s+2)(s +2s+2)
d and f only Obtain the inverse Laplace transform f () for the following: 2.8 5 6 4s a. $2+9 $2+4 s2+4 5 6 d. s(s +3) 2s +8 с. s2+4s+ 13 10 f. (s+3)(s+7 е. (s+3)(s +7)
Find the inverse Laplace transforms of (a) (b) (c) s 1 (2s +1) Y(s) = (822 5s + 8 (2s - 2) 21) Y(s) = Find the inverse Laplace transforms of (2s- 3)e-3,s 1) (2s (a) Y(s)2s+ ) (2s - 2) (c) Y(s) = (5-7)2 s 1 (2s +1) Y(s) = (822 5s + 8 (2s - 2) 21) Y(s) = Find the inverse Laplace transforms of (2s- 3)e-3,s 1) (2s (a) Y(s)2s+ ) (2s - 2) (c) Y(s) =...
1. Find the inverse laplace of the following: 12 a. 4 S 1 b. 52 + 2s +10 2 (s – 2)² +4 S C. S d. 2 S +65 +13 1 e. 52 +45 +4.
1 +s Find the inverse Laplace transforms of the following: a. F(s) = a (s+2)2 b. F(s) = -25- Hint: Complete the square in denominator 2s -1 s2-2s +10
Find Laplace inverse: 10 S-4 1- F(s) = 2- F(s) = 2 3- F(s) = 4- F(s) = 3249 2 5- F(s) = 52 +9 6- F(s) = 2 (s+3) S 7- F(s) = (s+1)(S-2) 10 8- F(s) = (s-3)(s+4) 9- F(s) = 35+1 s(s-1)(-4)
6. (a) Determine the inverse Laplace transform of F(8) 2s - 1 32 - 4s +6 (10 marks/ (b) Solve the initial value problem using the method of Laplace transform. 7+10y = 0, y(0) = 0, (0) --3. (20 marks) (c) Solve the initial value problem: 1 dy dy 4 dx2 + 4y = 0, y(0) -- da + (0) = -1 120 marks)