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i need help with #13 please explain in detail
11. State the interval. The interval is (0.506041,0.852655) 12. Interpret the interval. We are 95% confident that the populat
distributed but instead is skewed to the left and contains outliers. Meaning that the resulting 95% confidence interval may n
the proportion who exercise regularly? Part one: For females, what is the average height? Histogram of height 10 8 on Frequen
7. For females, what is the proportion that exercise regularly? Chart of exercise 20 15 Count 10 5 no yes exercise 9. Define
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Answer #1

Hi,

We have given that:

Confidence interval=(0.506041,0.852655)

This means we are 90%confident that population mean of populations proportion of female that exercise regularly is between 0.506041 and 0.852655.

Extra→Population mean interval of female who exercise regular=(Np',Np)=(30*0.506041,30*0.852655)=(15.181,25.5796)

Thanks!

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