Question

Review Constants The current shown in (Figure 1) is applied to a 350 nF capacitor. The initial voltage on the capacitor is zero. Part A Find the charge on the capacitor at t = 30 jus Express your answer to three significant figures and include the appropriate units. IT μΑ q= 25.103 O Submit Previous Answers Request Answer Part B Find the voltage on the capacitor at t = 50 js. Express your answer to three significant figures and include the appropriate units. Figure < 1 of 1 > НА ? v = 2.5• 103 V i (MA) Submit Previous Answers Request Answer 400 X Incorrect; Try Again; 4 attempts remaining 1 30 (us) 0 5 10 20 40 SO -300 Part C

Answer 1

The solution to the part a is shown in the above image.

Part from the figure, find the equation of current from t-20 to t=56 As it is a Af t=20 t= so Straight line with Slope. (-300,20) (oo) (yso) -) (4-0) (y-Y) C) (0-2) is equation of line between two points) 50 - 20 0-300 L y so t als 10 y = ilt) lict - sot & mA T a=t 10 P . Charge (a) = sidt 150 + 1 / (sot + 2 ) mCoulumb . Charge at t=30 (so (30)+ 10 Jane (1500+ 17 (x103 900 x 103 1.59 Coulumb.

The solution to the part b is shown in the above image.

The solution to the part c is shown in the above image.

tor Part - C a capacitor, the Capacitor Stores the energy in it only when it is not under uither charging (0v elischevroying conditions Ir mean that Current through Capacitor must be confount as the voltage acros ir be Comfount. will from the figure, the capacitor Stores energy only from t=s to t=20. Equation of current from t=5 to t=20 iLt) 400 MA. It i Constant Value). For Capacitor & sidt. 20 v 2. £ / 400 mA at 5 u= + 400 410 ²(E) 0 10 - * 400X10(20-5) 350010 30xd 17. 143 x 10 v ₂ c² 2 Energy stored in Captuitor. 2 x 350x10x (17.143410) 51.429 J.