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A hospital director is told that 79% of the treated patients are insured. The director wants to test the claim that the perce
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Answer #1

Ans a) There is sufficient evidence to support the claim that the percentage of the insured patient is less than 79%

Explanation:

Null Hypothesis:

H_{o}:p = 0.79

Alternate Hypothesis states that the percentage of insured patients is less than the expected percentage

H_{a}:p < 0.79

Sample proportion: \hat{p} = \frac{x}{n} = \frac{255}{340} = 0.75

Test statistics:

z = \frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

= \frac{0.75-0.79}{\sqrt{\frac{0.79(1-0.79)}{340}}}

= -1.81

Test statistics z = -1.81

P-value = 0.0351 /* we can find p-value using excel function: =NORM.S.DIST(-1.81,TRUE) */

Since P-value < 0.1 (we reject null Hypothesis)

Conclusion:There is sufficient evidence to support the claim that the percentage of the insured patient is less than 79%

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