Question

2. Find the value of that yields the probability shown. a. P(Z <=*)-0.2200 b. P(Z < **) -0.0001 C. P(Z > **)-0.0055 d. P(Z >
• For #2: a) P(Z < z*) = 0.3300 b) P(Z <z*) = 0.9901 c) P(Z > z*) = 0.0055 d) P(Z > z*) = 0.7995

2nd photo is just clearer numbers of 1st
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Answer #1

The solution to this problem is given by

(4) % Solution P(222*) = 0.3300 १। 2 < -५५) - 0.33 2 --0.44 (b) (742* ) O११० A80 P(2 2 9.33) 0.990 21 9.33 (C) P( 22 ) 0,0055

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