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Question 3 (2 points) Two identical light bulbs are arranged in a parallel circuit. If one of the bulbs is removed (leaving a
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00 Brightness - Power = NI R I R/2 R =) V v Ղ = ) >> R/ I= 218 2) I R I » R 2V 12 1 + 1 = 1 As the bulbe identical, - 1,-1,-1Now one of the bulb n remored, then have we R V does not change I = V/R 2. > Power 11 v R be bull &o, the power is not affect

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