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Tensile strength tests were carried out on two different grades of wire rod, resulting in the accompanying data. Grade Sample
State the conclusion in the problem context. Fail to reject Ho. The data suggests that the true average strength for the 1078
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Answer #1

a)

HO: μ1064 - μ1078 = -10 Ha: μ1064 - 10 μη78

pop 1 pop 2
sample mean x = 105.40 124.70
std deviation σ= 1.100 2.100
sample size n= 126 126
std error σx1-x2=√(σ21/n122/n2)    = 0.211
test stat z =(x1-x2o)/σx1-x2     = -44.04
p value : = 0.0000 (from excel:1*normsdist(-44.04)

10 kg/mm2. Reject HO. The data suggests that the true average strength for the 1078 grade exceeds that for the 1064 grade by

b)

Point estimate of difference '=x1-x2 = -19.300
for 95 % CI value of z= 1.960 from excel:normsinv((1+0.95)/2)
margin of error E=z*std error = 0.414
lower bound=(x1-x2)-E = -19.71
Upper bound=(x1-x2)+E = -18.89
from above 95% confidence interval for population mean =(-19.71 , -18.89)
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