false positive = P(positive|no cancer)=0.05
false negative = P(negative|cancer) = 0.04
P(cancer) = 0.05
P(positive) = P(cancer and positive) * P(no cancer and positive)
=(1-0.04)*0.05+0.05*(1-0.05)= 0.0955
1) P(cancer| positive) = (1-0.04)*0.05/0.0955 = 0.502617801
2) P(both test positive) = 0.0955^2 = 0.00912025
P(cancer | both positive) =(0.05*0.96)^2/0.00912025 =
0.252624654
To prevent developing a certain type of cancer, Health Canada organize a di- agnostic test. The...
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To prevent developing a certain type of cancer, Health Canada organize a di-agnostic test. The false positive and negative rates for this diagnostic test arefive percent and four percent, respectively. Assume that five percent of the population has this type of cancer.1. If a randomly selected person has a positive test result, what is the prob-ability that the person has this type of cancer?2. The test is administrated twice on the same patient. Assume that the test results are independent...
Exercise 10: To prevent developing a certain type of cancer, Health Canada organize a di- agnostic test. The false positive and negative rates for this diagnostic test are five percent and four percent, respectively. Assume that five percent of the population has this type of cancer. 1. If a randomly selected person has a positive test result, what is the prob- ability that the person has this type of cancer? 2. The test is administrated twice on the same patient....
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