The cross section of a plastic tube for use in pulmonary
resuscitators is normally
distributed with a mean of 12.5mm2 and a standard deviation of 0.2
mm2. When the
cross section is less than 12mm2 or more than 13 mm2, the tube will
not be adjusted
properly. What is the probability that a randomly selected tube
will be adjusted
properly?
A. 0.9538 B. 0.9998 C. 0.9890 D. 0.9745 E. 0.9876
Solution :
Given that ,
mean =
= 12.5
standard deviation =
= 0.2
P(12 < x < 13) = P[(12 - 12.5)/ 0.2) < (x - ) /
<
(13 - 12.5) / 0.2) ]
= P(-2.50 < z < 2.50)
= P(z < 2.50) - P(z < -2.50)
Using z table,
= 0.9938 - 0.0062
= 0.9876
correct option is = E
The cross section of a plastic tube for use in pulmonary resuscitators is normally distributed with...
The cross section of a plastic tube for use in pulmonary resuscitators is normally distributed with a mean of 12.5mm and a standard deviation of 0.2 mm? When the cross section is less than 12mm? or more than 13 mm?, the tube will not be adjusted properly. What is the probability that a randomly selected tube will be adjusted properly? A. 0.9538 B. 0.9998 C. 0.9890 D. 0.9745 E. 0.9876
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