a)
The confidence interval can be calulated using -
The mean is 6 whereas the standard deviation comes out to be 2.6.
For 95% the Z value is 1.960
6 +- 1.96*[2.6 / (6)**0.5]
6 +- 1.96*[2.6/2.5]
6 +- 1.96*1.064
6 +- 2.08 = 3.91 and 8.08
The 95% confidence interval is (3.91, 8.08).
b)
Increasing the sample size decreases the width of confidence intervals, because it decreases the standard error.
Option A is the right answer.
The random sample shown below was selected from a normal distribution. 8, 10, 6, 4, 5,...
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