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A simple random sample of size n=81 is obtained from a population with u = 73 and o = 36. (a) Describe the sampling distribut
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Answer #1

Solution :

Given that ,

a) Correct option is C

b) \mu \bar x = 73

\sigma\bar x = \sigma / \sqrt n = 36 / \sqrt 81 = 4

P(\bar x > 77.6) = 1 - P(\bar x < 77.6 )

= 1 - P[(\bar x - \mu \bar x ) / \sigma \bar x < (77.6 - 73) / 4]

= 1 - P(z < 1.15)   

= 1 - 0.8749

= 0.1251

c) P(\bar x < 65) = P((\bar x - \mu \bar x ) / \sigma \bar x < (65 - 73) / 4 )

= P(z < - 2)

Using z table

= 0.0228

d) P(70.4 < \bar x < 81 )  

= P[(70.4 - 73) / < (\bar x - \mu \bar x) / \sigma \bar x < (81 -73) / 4)]

= P( - 0.62 < Z < 2)

= P(Z < 2) - P(Z < - 0.62)

Using z table,  

= 0.9772 - 0.2676  

= 0.7096

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