2XY (aq) → X2 (aq) + Y2 (aq) in 1.0 L reaction vessel...
Based on the chemical equation and picture, what would the Kc value be?
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2XY (aq) → X2 (aq) + Y2 (aq) in 1.0 L reaction vessel... Based on the...
QUESTION 2 Calculate and simplify det if f(x,y) = O x2 - y2 + 2xy (x2 + y2)2 O 4x(+- x² + 3y2) (x² + y²)3 o 4x(x² – 3y?) (x² + y²)3 OO O x2 - y2 + 2xy (x² + y²)?
(2xy - y2 + 2) dx + (x2 – 2xy – 3) dy=0 (Exact Equation)
Show that if x and y are real numbers, x2 + y2 >= 2xy and
(x + y)2 >= 4xy; When does equality hold (with proof)?
Show that if x and y are real numbers, x2 + y2 2xy and (x y) 2Hry. When does equality hold (with proof)?
Consider the reaction: Mg(OH)2 (s) = Mg(aq) + 2 OH- (aq) At equilibrium, a 1.0 L reaction vessel contains 5.3 moles of Mg(OH)2 and concentrations of 0.0080 M and 0.010 M of Mg and OH respectively. What is Kc for this equilibrium? Consider the reaction: N2 (g) + 3 Br(g) = 2 NBr) (g) At equilibrium, the concentrations of Nz and Bra are 0.34 M and 0.70 M respectively, and the concentration of NBrs is 0.090 M. What is Kc...
Calculate E°ceII for the foIIowing reaction as writen (in volts). X(s) + Y2+(aq) → X2+(aq) + Y(s) X2+(aq) + 2 e- → X(s) Standard eIectrode potential (E°) values: E° = 2.50 V Y2+(aq) + 2 e- → Y(s) E° = 1.00 V
--- T2-1 (20 Points): Find the P.S. of the IVP: x2 + 2xy + y2 1+ (x + y)2 y(x = 0) = 4 Primes denote derivatives WRT X.
Find the P.S. of the IVP: x2 + 2xy + y2 1+ (x + y)2 y(x = 0) = 4 Primes denote derivatives WRT X. (y'a
Calculate pressure (at STP) in 10.0 L vessel after reaction of 1.0 L hydrochloric acid (concentration 35 % and density 1.28 g/cub.cm.) with 1.0 kg of limestone (calcium carbonate with 4.0 % inert impurities). Yield of reaction 97 %. The chemical equation is: 2HCl+CaCO3=CaCl2+H2O+CO2
For the limaçon x2 + y2 = (x2 + y2 - 2x)? (Exercise 24 in Section 3.5), verify that the points P(1.0) and 0(3,0) are on the graph and are the rightmost points (tangent line is vertical). (a) plug in x=1, y=0, both sides of the equation are equal to (b) plug in x=3, y=0, both sides of the equation are equal to (c) Find y'at P(1,0): y'I=1.y=0 = (d) Find y' at Q(3,0): y'Ix=3.y=0 =
2. Solve the differential equation (2xy + y)dx + (x2 + 3.ry2 – 2y)dy = 0. Answer: x²y + xy3 – y2 = C.