Question

Assuming an ideal op-amp (1)find the 3dB frequency of the circuit, if R1=1.5 KΩ, R2=13.2 KΩ, R3=20 KΩ, and C=5 nF

- C R2 R1 + Vi(jw) Vo R3 H HI-

2)Consider the above circuit with the component values: R1=13.2 KΩ, R2= 795.77 Ω, R3=20 KΩ, and C=100 nF.  Find the angle of the transfer function in degrees at 2KHz .

Answer 1

a میں کر с th AI VN I + funt the Center into ) terminals of op-amp R2 RI Vo(s) to be ideal nsidering op - amp Can obseave that op-amp so VN = O. .. Up= 0 v; (s) RI Current does not flow through have We negative feed back Up = VN - Current I = flow through Resistor So entire Current R2 and a The Impedence provided by Capacitor is

R2 of and The paralle will provide с Combination impedence Rallisce R2. Sc R2 + Sc R2 Z It SCR2 Now Vo (s) ZIT VN (Applying Kul) - R2 ve(s) It SCR2 RI Vies) CA UN = 0 & I = Ri Ve(s) - R2 RI Vics) It SCR2

1+ W= 'Relai Vols) Vils) 1/R2C. at R2C Rec Vols) Relri Vics) yz which obtained frequency So cut off frequency at 3-dB is fc = at Rec R2 = 13.2 kv R3=20kn R = 1.5kn c=5nf 3dB frequency PsdB 2 x 7 x 13.2 X103 x5X10 9 fade dB = 2.4 KHZ

(2) Transfer function R2 12/R1 Vout (s) Vin(s) 1+ jwcR2 $ = - tan! (wcR2) = - tani ton" (20 2UX QX103 x 400xio X 795.77) 450

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