Please Help with Part C and D!! Determine the number of degrees of freedom for the...
Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answers down to the nearest whole number.) (a) m = 10, n = 15, 51 = 4.0, S2 = 5.0 X (b) m = 10, n = 18, S1 = 4.0, S2 = 5.0 m = 10, n = 18, S1 = 3.0, 52 = 5.0 (d) m = 12, n = 21, 51 = 4.0, S2 =...
Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answers down to the nearest whole number.) (a) m = 12, n = 15, $1 = 5.0, 52 = 6.0 (b) m = 12, n = 18, S, = 5.0, S2 = 6.0 (c) m = 12, n = 18,51 = 3.0, 52 = 6.0 (d) m = 10, n = 21, S, = 5.0, S2 = 6.0
Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answers down to the nearest whole number.) (a) m = 12, n = 10, S1 = 3.0, 52 = 4.0 (b) 15 m = 12, n = 18, s1 = 3.0, S2 = 4.0 x m = 12, n = 18, S1 = 2.0, S2 = 4.0 (c) 19 m = 10, n = 24, $1 = 3.0,...
Determine the number of degrees of freedom for the two-sample t test or Clin each of the following situations. (Round your answers down to the nearest whole number.) (a) m - 10, n = 10, $, - 4.0, $2 6.0 (b) m-10, n. 15, 5, -4.0, , -6.0 (c) m-10, n = 15,5,- 2.0, 52 - 6.0 (d) m = 12, n = 24, 5, - 4.0, S2 = 6.0
Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answers down to the nearest whole number.) (a) m = 12, n = 15, 51 = 5.0, 5 2 = 6,0 (b) m - 12, n = 18, 51 = 5.0, 5 2 = 6.0 (c) m = 12, n = 18, 51 = 2.0, 52 = 6.0 (d) m - 10, = 24, 51 = 5.0, 5...
please explain.
Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answers down to the nearest whole number (a) m-12, n 10, s,3.0, s, 6.0 (b) m 12, n 18, s, 3.0, s, 6.0 (c) m-12, n 18, s, 2.0, 5, 6.0 (d) m 10, n-24, s, 3.0, s, 6.0 You may need to use the appropriate table in the Appendix of Tables to answer this question
Please help with BOTH
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Tensile strength tests were carried out on two different grades of wire rod, resulting in the accompanying data. Grade AISI 1064 AISI 1078 Sample Size m = 129 n = 129 Sample Mean (kg/mm) x= 109.3 y = 129.9 Sample SD 51 = 1.1 52 = 2.0 (a) Does the data provide compelling evidence for concluding that true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10...
Find the degrees of freedom, df to test the hypothesis that μ1 > μ2. Two samples are randomly selected and come from populations that are normal. The sample statistics are given below. n1 = 40 n2 = 40 x1= 63.0 x2= 61.5 s1 = 15.8 s2 = 29.7 Round your answer DOWN to the nearest integer.
Please help find the degrees of freedom Using s1 = 3 and s2 = 4, we can compute the t value corresponding to the test statistic x1 − x2 = −2. Recall that n1 = 49 and n2 = 64. We will also need the degrees of freedom for this sample statistic, which is given by the smaller of n1 − 1 and n2 − 1. Since n1 − 1 = 48 and n2 − 1 = 63, find that d.f. =
Suppose, and level 0.01 to test H are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. Use the two-sample test at significance H - - -10 versus - # < -10 for the following data: m., 113.2, 5.0, - 129.3, and s, - 5.35. Calculate the test statistic and determine the P-value. (Round your test statistic to two decintal places and your value to three decimal places)...