Using Minitab,
The null hypothesis states that the median equals 2. Because the p-value is approximately 0.9423, which is greater than the significance level of 0.05, we cannot reject the null hypothesis.
A study of the surface roughness of coated interior pipe used in oil fields was conducted....
A study of the surface roughness of coated interior pipe used in old was conducted. The data in micrometers) for 20 sampled pipe ons we reproduced in the table below. Conducta sormetto whether the median surface roughness of coated interior pipe, differs from 2 micrometers. Test using 0.10 1.87 2.65 2.48 142 198 1.35 2.65 2.70 2.78 2.75 Fuldata set 2.01 2.50 1.47 2.35 1.72 2.35 1.86 2.25 2.65 2.24 What are the null and afternative hypotheses? O A. Hon=13...
uc A study of the surface roughness of coated interior pipe used in oil fields was conducted. The data in micrometers) for 20 sampled pipe sections are reproduced in the table below. Conduct nonparametric test to determine whether the median surface roughness of coated interior pipe, differs from 2 micrometers. Test using a 0.10 2.43 1.80 1.78 2.52 1.25 236 237 2.20 1.34 2.62 Fuldataset 1.44 1.39 1.46 2.37 2.44 2.09 1.57 2.10 2.80 1.64 What are the null and...
2.73 Surface roughness of pipe. Refer to the Anti-corrosion Methods and Materials (Vol. 50, 2003) study of the sur- face roughness of coated oil field pipes, Exercise 2.20 (p. 37). The data (in micrometers) are repeated in the table. Give an interval that will likely contain about 95% of all coated pipe roughness measurements. ROUGHPIPE - - - 1.72 2.50 2.16 2.57 2.64 1.26 2.13 1.06 2.24 2.31 2.03 1.09 1.40 2.05 1.19 2.13 1.27 1.51 2.41 1.95 - -...
REGRESSION 2 • reg bught cigs faminc male Source SS df MS = = Model Residual 20477.12 554134.6 3 6825.70666 1,384 400.386272 Number of obs F(3, 1384) Prob > R-squared Adj R-squared Root MSE 1,388 17.05 0.0000 0.0356 0.0335 20.01 - Total 574611.72 1,387 414.283864 bwght Coef. Std. Err. Piti (95Conf. Intervall cigs famine male _cons -.4610457 0913378 .09687980291453 3.113968 1.076396 115.2277 1.20788 -5.050.000 3.32 0.001 2.89 0.004 95.400.000 -.6402212 .0397062 1.002423 112.8582 - 2818702 .1540535 5.225513 117.5972 f) Conduct...
1. Two manufacturing processes are being compared to try to reduce the number of defective products made. During 8 shifts for each process, the following results were observed: Line A Line B n 181 | 187 Based on a 5% significance level, did line B have a larger average than line A? *Use the tables I gave you in the handouts for the critical values *Use the appropriate test statistic value, NOT the p-value method *Use and show the 5...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...