A bag of M&MS was randomly selected from the grocery store shelf, and the color counts were: Brown 20, Red 5, Yellow 10, Orange 4, Green 5, Blue 6. Mars Inc. claims that they produce M&Ms with the following distributions Brown 30% Red 20% Yellow 20% Orange 10% Green 10% Blue 10%.
1. n = 50, is there evidence of difference between the random bag that was picked and Mars Inc.'s claims?
2. Graph the results.
Therefore the claim by Mars Inc is accepted at level of
significance 0.05.
p-value = P(X> 4.567), where X~chi-square with d.f =5
therefore p-value = 0.47096
A bag of M&MS was randomly selected from the grocery store shelf, and the color counts...
Mars Inc, claims that they produce M&Ms with the following distributions: Brown Orange 30% Red 1046 Green 20% 10% Yellow Blue 20% 10% A bag of M&Ms was randomly selected from the grocery store shelf, and the color counts were: Brown 22 Orange 14 Red Green 22 Yellow 16 Blue 20 15 Using the goodness of fittest (a -0.10) to determine if the proportion of M&Ms is what is claimed. Select the [p-value, Decision to Reject (RH) or Failure to...
Mars Inc. claims that they produce M&Ms with the following distributions: Brown 30% Red 20% Yellow 20% Orange 10% Green 10% Blue 10% A bag of M&Ms was randomly selected from the grocery store shelf, and the color counts were: Brown 22 Red 24 Yellow 19 Orange 14 Green 15 Blue 15 Using the χ2 goodness of fit test to determine if the proportion of M&Ms is what is claimed, what is the test statistic? a) χ2 = 8.049 b)...
Suppose you open a bag of M&Ms and count the number of M&Ms you have of each color. Suppose there were the following: Qty 4 blue Qty 4 orange Qty 1 yellow Qty 1 green Qty 3 brown Qty 2 red Calculate the proportion of each color (round to 3 decimals) Color Proportion Blue Orange Yellow Green Brown Red
4) In a 1.69oz M&Ms bag there are 13 blue, 11 green, 8 orange, 7 yellow, 7 red and 7 brown M&Ms. If you randomly picked two M&Ms from the bag and ate them, what is the probability that you ate all green M&Ms? (10pts)
10.9 The manufacturer of M&M's claims the following color breakdown: 24% blue, 20% orange, 16% green, 14% yellow, 13% red, and 13% brown. A randomly selected bag of M&M's had 103 candies and yielded the following colors.
A manufacturer of colored candies states that 13% of the candies in a bag should be brown, 14% yellow, 13% red, 24% blue, 20% orange, and 16% green. A student randomly selected a bag of colored candies. He counted the number of candies of each color and obtained the results shown in the table. Test whether the bag of colored candies follows the distribution stated above at the α=0.05 level of significance. Color Brown Yellow Red Blue Orange Green Frequency...
A manufacturer of colored candies states that 13 % of the candies in a bag should be brown, 14 % yellow, 13 % red, 24 %blue, 20 % orange, and 16 % green. A student randomly selected a bag of colored candies. He counted the number of candies of each color and obtained the results shown in the table. Test whether the bag of colored candies follows the distribution stated above at the alpha equals 0.05 level of significance. (A)...
State the null and alternative hypotheses. It has been rumored that the color distribution of M&M’s is 30% brown, 20% yellow, 20% red, 10% orange, 10% blue, and 10% green. You suspect this rumor is incorrect and decide to count how many of each color are contained in a randomly chosen bag in order to perform a Chi-Square goodness-of-fit test at a 5% significance level. Color Brown Yellow Red Orange Blue Green Total Observed 27 16 21 12 9 15...
A manufacturer of colored candies states that 13% of the candies in a bag should be brown, 14% yellow, 13% red, 24% blue, 20% orange, and 16% green. A student randomly selected a bag of colored candies. He counted the number of candies of each color and obtained the results shown in the table. Test whether the bag of colored candies follows the distribution stated above at the α = 0.05 level of significance. 囲Click the icon to view, the...