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2.77 g of an unknown acid, HA, is dissolved in enough water to provide 25.0 mL...

2.77 g of an unknown acid, HA, is dissolved in enough water to provide 25.0 mL of solution. The pH of this HA (aq) solution is 1.33. This solution is titrated with a 0.250 M NaOH solution. 44.2 mL of this NaOH solution is needed to reach the equivalence point.

(a) (2 marks) What is the molar mass of HA?

(b) (2 marks) What is the value of pKa for HA (aq)?

(c) (2 marks) What is the pH at the equivalence point?

(d) (2 mark) What is the pH after one third of the titration when you still have twice the amount of HA (aq) than A- (aq)?
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