Question

A manufacturer of paper used for packaging requires a minimum strength of 1500 g/cm2. To check on the quality of the paper, a random sample of 10 pieces of paper is selected each hour from the previous hour's production and a strength measurement is recorded for each. The standard deviation σ of the strength measurements, computed by pooling the sum of squares of deviations of many samples, is known to equal 150 g/cm2, and the strength measurements are normally distributed.

1. If the mean of the population of strength measurements is 1550 g/cm

2, what is the approximate probability that, for a random sample of n = 10 test pieces of paper, x < 1500? 2. What value would you select for the mean paper strength μ in order that P(x < 1500) be equal to 0.001?

Answer 1

Answer:-

In this n=\l : A = 1550 : 03 150 Q) Pt T c 1500) s X- (500-1550 아 (Sook | PCz] b) 2 10.1335 PCT (50) = 0.00( 째 (So-H 여금 150HT 품 2000/ 1500 - P 1501 2 -3.04 H = 1500+3.01(15 1639.75 D.

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