Starting with 0.100 mol each of CO(g) and H2O(g) in a 5.00 L flask at 600...

Question

Question

Starting with 0.100 mol each of CO(g) and H₂O(g) in a 5.00 L flask at 600 K;

CO(g) + H₂O(g) CO₂(g) + H₂ (g) K_c = 23.2 at 600 K

Answer 1

Answer #1

Solution - The The equillibeuium reaction is CO(g) + H₂O(g) - CO2 (g) + H₂CG) Initial moles 0-100 mol 0.100 mol Initial conce

Answer 2

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