0.35g of an unknown compound dissolved in 100.0ml of water ahas an osmotic pressure of 32.6...
Homework Answers
π=mRT
= (W2*1000*RT)/(M2*w1)
M2=w2*1000*RT/π*w1
W2=0.35g, R=0.0821,T =288 ,
π =(32.6/760)=0.043 atm, w1=100g
=(0.35*1000*0.0821*288)/(0.043*100)
=1.92*10^3g
=1.92kg
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