at 25 degrees celsius the Ka for formic acid is 1.8 x 10^-4. what is the...

Question

Question

at 25 degrees celsius the Ka for formic acid is 1.8 x 10^-4. what is the pH of a 0.10 M aqueous solution of lithium formate

Answer 1

Answer #1

For a salt of any weak acid, we have to apply salt hydrolysis equation to get the pH of that solution. The equation is:

$pH=7+\frac{1}{2}\, pK_a+\frac{1}{2}\, log\, C$

C is the salt concentration. Now,

pK_a = - log (1.8 x 10^-4) = 3.745

Thus,

$pH=7+\frac{1}{2}\times 3.745+\frac{1}{2}\times log(0.10)=7+1.8725-0.5=8.37$

So, the pH = 8.37

Answer 2

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