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Questions We disolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.9 mL of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pKa value of HA(aq)? (c) (2 points) What is the pH at the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 43.7 mL of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pK, value of HA(aq)? (c) (2 points) What is the pH at the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 43.4 ml of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pk, value of HA(aq)? (c) (2 points) What is the pH at the...
We dissolve 2.77 g of an unknown acid, HA, enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 43.2 mL of the NaOH solution to reach the equivalence point (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pK, value of HA(aq)? (c) (2 points) What is the pH at the equivalence...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.1 mL of the NaOH solution to reach the equivalence point.What is the pH at the equivalence point and What is the pH one third along the titration when you still have twice as much HA(aq) as A-(aq)?
Question 5: We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 44.8 mL of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pK, value of HA(aq)? (c) (2 points) What is the pH...
Question 5: We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 40.6 mL of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pk, value of HA(aq)? () (2 points) What is the pH...
Question 5 We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.7 ml of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pk, value of HA(aq)? (0) (2 points) What is the pH...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 42.2 mL of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pKa value of HA(aq)? (c) (2 points) What is the pH at the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 42.5 mL of the NaOH solution to reach the equivalence point. (a) (2 points) What is the molar mass of HA? (b) (2 points) What is the pKa value of HA(aq)? (c) (2 points) What is the pH at the...