1. Last option is correct. as carboxylic acid is most acidic in nature .
For acidity look stability of conjugate baseobtained by removal of acidic proton.
more the resonance stability of base increases also hyperconjugation is seen n case of enolate for aldehyde and ketone.
2. i is correct option as LiALH4 is a strong reducting agent that reduces aldehyde to alcohol.
3.last option is correct.It is necessary, to achieve complete conversion of aldehyde or ketone reactants to their enolate conjugate bases by treatment with a very strong base (pKa > 25) in a non-hydroxylic solvent.
Arrange the indicated protons by acidity, most acidic first: H I II III IV IV>II> III...
Question 33 (4 points) Arrange the indicated protons by acidity, most acidic first: So yo H I II III IV II >I> III > IV O1> II > III > IV II > I > IV> III O1>IV > III > II
Arrange the indicated protons by acidity, most acidic first: H ول است H E I II III IV
Arrange the designated protons by chemical shift (d), highest to lowest chemical shift value (delta). HI CH, IV 3 CHE Hoc OH>I>II> IV II > III >I> IV OIV>II> III > 1 1> III > II > IV Predict the product of this reaction: H30* ОН heat он 1. ГОН 1 Оно ОН о ОН
please help with these ASAP, thanks! Arrange these compounds in order of decreasing acidity. List the most acidic compound first. 11 III Thor IV. OH OH ОН ОН O I>IV > I > III 01> II > III > IV III >I> II > IV OIV > II >I> III What is the major product in the following reaction? 1. CH3l (excess) ? NH2 2. Ag20, H20, heat HN
What happens in the first step of this reaction? & H + H2O OH OH The spoxygen of the ester becomes protonated The carbonyl carbon becomes protonated The water becomes protonated The carbonyl oxygen becomes protonated Which bases among the following is/are used for reversible enolate formation of acetone? LDA NaOH NaH NaOM NaNH2 - II III IV O II, IV, and V O II and IV OI, III, and V OIV only
Question 12 Rank the indicated protons in decreasing order of acidity. = I III H O I>III>II II>III>I I>II>III II>I>III III>II>I
Arrange the molecules shown below in the order of DESCENDING acidity. H Η Η H - П III IV СА. 1>I>IV>III I>IV>I|I>11 OB. IV>II>II>I Ос. D. III>IV>I>11
Please help...and explain.. Rank the acidity of the protons shown in the picture (from most acidic to least) I > II > III = IV IV > I = II > III IV > I > II > II I > II > IV > III What accounts for the difference between the acidity of proton (IV) and protons (I and II)? (may be more than one answer) Feature 1: energy and entropy stabilization Feature 2: energy and entropy stabilization...
Rank the following compounds in order of increasing acidity, putting the least acidic first. alon F. ОН Br ОН ОН ІІ ІІ IV ОІ<IV <<Ш ОІ<< < IV ОШ <II <IV <I OIH <IV <II <I
Rank the acidity of the following compounds in order of most acidic to least acidic. H ОН HCI HB II III IV HTML EC