HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.055 M in A-(aq)? The temperature is 25oC.
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HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is...
(a) HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.066 M in A-(aq)? The temperature is 25oC. (b) For the reaction A(g) ⇋ B(g) + C(g), the equilibrium constant is 1.80 at 25.0oC and 4.36 at 75.0oC. Assuming ΔH and ΔS do not change with the temperature, calculate the value of the equilibrium constant at 50.0oC and the value of ΔSuniverse at 50.0oC.
(a) HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.065 M in A-(aq)? The temperature is 25oC. (b) For the reaction A(g) ⇋ B(g) + C(g), the equilibrium constant is 1.80 at 25.0oC and 4.00 at 75.0oC. Assuming ΔH and ΔS do not change with the temperature, calculate the value of the equilibrium constant at 50.0oC and the value of ΔSuniverse at 50.0oC
(a) HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.068 M in A-(aq)? The temperature is 25oC. (b) For the reaction A(g) ⇋ B(g) + C(g), the equilibrium constant is 1.80 at 25.0oC and 4.95 at 75.0oC. Assuming ΔH and ΔS do not change with the temperature, calculate the value of the equilibrium constant at 50.0oC and the value of ΔSuniverse at 50.0oC.
(a) HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.065 M in A-(aq)? The temperature is 25oC. (b) For the reaction A(g) ⇋ B(g) + C(g), the equilibrium constant is 1.80 at 25.0oC and 4.14 at 75.0oC. Assuming ΔH and ΔS do not change with the temperature, calculate the value of the equilibrium constant at 50.0oC and the value of ΔSuniverse at 50.0oC.
(a) HA (aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a 0.061 M solution in A- (aq)? The temperature is 25oC. (b) For the reaction A (g) ⇋ B (g) + C (g), the equilibrium constant is 1.80 at 25.0oC and 4.46 at 75.0oC. Making the approximation that ΔH and ΔS do not change with temperature, calculate the value of the equilibrium constant at 50.0oC as well as the...
#4 (a) HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.061 M in A-(aq)? The temperature is 25oC. (b) For the reaction A(g) ⇋ B(g) + C(g), the equilibrium constant is 1.80 at 25.0oC and 4.14 at 75.0oC. Assuming ΔH and ΔS do not change with the temperature, calculate the value of the equilibrium constant at 50.0oC and the value of ΔSuniverse at 50.0oC.
a) (4 marks) HA (aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a 0.061 M solution in A- (aq)? The temperature is 25oC. (b) (4 points) For the reaction A (g) ⇋ B (g) + C (g), the equilibrium constant is 1.80 at 25.0oC and 4.71 at 75.0oC. Making the approximation that ΔH and ΔS do not change with temperature, calculate the value of the equilibrium constant at 50.0oC...
#3 (a) HA (aq) is a weak acid with a dissociation constant, Ka, of 2.0 x 10-15. What is the pH of a 0.04 M solution in A- (aq)? The temperature is 25oC. (b) For the reaction A (g) ⇋ B (g) + C (g), the equilibrium constant is 2 at 25.0oC and 3 at 75.0oC. Making the approximation that ΔH and ΔS do not change with temperature, calculate the value of the equilibrium constant at 50.0oC as well as...
Consider weak monoprotic acid HA(aq) D H+(aq) + A–(aq) with Ka = 4.0 x 10–5 and pKa = 4.40. A solution is composed of 900.0 mL of 0.090 M HA and 0.080 M NaA (10 points). (a) Calculate the pH of this solution. (b) Calculate the pH of the above solution following the addition of 10.00 mL of 2.0 M NaOH (a strong base).
Question 1 : HA is a weak acid. Its ionization constant, Ka, is 1.2 x 10-13. Calculate the pH of an aqueous solution with an initial NaA concentration of 0.075 M. Question 2 : We place 0.143 mol of a weak acid, HA, in enough water to produce 1.00 L of solution. The final pH of the solution is 1.28 . Calculate the ionization contant, Ka, of HA. Question 3 : We place 0.661 mol of a weak acid, HA,...