Let X be the breaking strength of the rivet
X~ Normal ( 5500, 307)
Sample size , n= 16
Let be the sample mean of the 16 samples
~ Normal ( 5500, )
P( 5456.25 < < 5566.01) = P( < < )
= P( -0.57< z < 0.86)
= P( z < 0.86) - P(z < -0.57)
= P(z < 0.86) - 1 + P(z < 0.57)
= 0.80511 - 1 + 0.71566
= 0.52077
The breaking strength of a certain rivet used in a machine engine is normally distributed with...
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