Question

O Fig. H 12. The thin cylindrical shell in Fig. H approaches the inclined plane at the right with velocity v, as shown, rolls up this plane, until brought to rest by gravity, and then rolls back down again. What will be its velocity ve as it finally rolls to the left along the horizontal plane? Assume that the shell at all times rolls without slipping and that there is no rebound after impacts. Ans. v= x (2-cos ay)

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Answer 1

The given answer is wrong. When the cylinder comes down to the horizontal palne again the velocity will not change. It will be Vc again in horizontal plane. Because of energy conservation. As there is no dissipation force like friction, even cylinder rolls without slipping all the time, so energy will conserve throughout the process and velocity will remain Vc in horizontal palne. The given answer is wrong, please check the source.