Homework Answers
Average arrival rate, λ = 4 per hour
Average service rate, μ = 8 per hour
(a)
The average number waiting, Lq = λ2 / {μ.(μ - λ)} = (4^2)/(8*(8 - 4)) = 0.50
(b)
The average number in the shop, Ls = Lq + λ/μ = 0.50 + 4/8 = 1.0
(c)
The average time in the queue, Wq = Lq / λ = 0.5/4 = 0.125 hours = 7.5 minutes
(d)
The total time in the shop, Ws = Ls / λ = 1/4 = 0.25 hours = 15 minutes
(e)
The percentage of time busy = λ/μ = 4/8 = 0.5 or 50%
Add Answer to:
please answer A-E
C. Time in queve
D. Total time
E. Time he is busy
Customers...
Customers arrive at Rich Dunn's Styling Shop at a rate of 2 per hour, distributed in...
Customers arrive at Rich Dunn's Styling Shop at a rate of 2 per hour, distributed in a Poisson fashion. Service times follow a negative exponential distribution, and Rich can perform an average of 5 haircuts per hour. customers (round your response to two decimal places). a) The average number of customers waiting for haircuts = customers (round your response to two decimal places). b) The average number of customers in the shop = c) The average time a customer waits...
arive at Rich Dunn's Styling Shop at a rate of 3 per hour, distibuted in a...
arive at Rich Dunn's Styling Shop at a rate of 3 per hour, distibuted in a Poesson fashion Service times follow a negatve exponential average of 6 haircuts per hour a) The average number of customers waiting for harots-□ customers oound your response to Mo domal places b) The average number of customers in the shop customers (round your response to two decimal places) c) The average time a customer wats unts it is his or her turn minutes (round...
Benny the Barber owns a one-chair shop. At barber college, they told Benny that his customers...
Benny the Barber owns a one-chair shop. At barber college, they told Benny that his customers would exhibit a Poisson arrival distribution and that he would provide an exponential service distribution. His market survey data indicate that customers arrive at a rate of 2.0 per hour. It will take Benny an average of 22 minutes to give a haircut. Based on these figures, find the following: a. The average number of customers waiting. (Round your intermediate calculations to 3 decimal...
5. A shop has an average of five customers per hour (a) Assume that the time T between any two cu...
A shop has an average of five customers per hour
5. A shop has an average of five customers per hour (a) Assume that the time T between any two customers' arrivals is an exponential random variable. (b) Assume that the number of customers who arrive during a given time period is Poisson. What (c) Let Y, be exponential random variables modeling the time between the ith and i+1st c What is the probability that no customer arrives in the...
Problem 15-9 (Algorithmic) Marty's Barber Shop has one barber. Customers have an arrival rate of 2.3...
Problem 15-9 (Algorithmic) Marty's Barber Shop has one barber. Customers have an arrival rate of 2.3 customers per hour, and haircuts are given with a service rate of 4 per hour. Use the Poisson arrivals and exponential service times model to answer the following questions: What is the probability that no units are in the system? If required, round your answer to four decimal places. P0 = What is the probability that one customer is receiving a haircut and no...
Benny the Barber owns a one-chair shop. At barber college, they told Benny that his customers...
Benny the Barber owns a one-chair shop. At barber college, they told Benny that his customers would exhibit a Poisson arrival distribution and that he would provide an exponential service distribution. His market survey data indicate that customers arrive at a rate of 2.0 per hour. It will take Benny an average of 26 minutes to give a haircut. Based on these figures, find the following: a. The average number of customers waiting. (Round your intermediate calculations to 3 decimal...
A small town with one hospital has 4 ambulances to supply ambulance service. Requests for ambulances...
A small town with one hospital has 4 ambulances to supply ambulance service. Requests for ambulances during nonholiday weekends average 0.68 per hour and tend to be Poisson-distributed. Travel and assistance time averages 2.40 hours per call and follows an exponential distribution Use Table 1. a. Find system utilization. (Round your answer to the nearest whole percent. Omit the "%" sign in your response.) System utilization % b. Find the average number of customers waiting. (Round your answer...
Calls arrive at Lynn Ann Fish's hotel switchboard at a rate of 1.5 per minute. The...
Calls arrive at Lynn Ann Fish's hotel switchboard at a rate of 1.5 per minute. The average time to handle each is 10 seconds. There is only one switchboard operator at the current time. The Poisson and negative exponential distributions appear to be relevant in this situation. a) The probability that the operator is busy = 0.25 (round your response to two decimal places). b) The average time that a caller must wait before reaching the operator = 0.06 minutes...
Customers arrive at the coffee shop in Bilkent FBA atrium, with a mean rate of 80 per hour (assume Poisson). It takes the barista, on average 30 seconds per cup of coffee (assume Exponential). Assume...
Customers arrive at the coffee shop in Bilkent FBA atrium, with a mean rate of 80 per hour (assume Poisson). It takes the barista, on average 30 seconds per cup of coffee (assume Exponential). Assume also that each customer buys only one cup. Determine: (a) The average number of customers waiting in line. (b) The average time customers spend in the system. (c) The average number of customers in the system. (d) The probability that a customer will not have...
15 customers arrive every hour at Andy Johnson's food truck when it parks outside the Orlando...
15 customers arrive every hour at Andy Johnson's food truck
when it parks outside the Orlando Courthouse from...
Table: Average Number of Customer in Waiting
Line
Poisson Arrivals, Exponential Service Times
Number of Service Channels, M
rhoρ
1
2
3
4
5
0.1
0.0111
0.15
0.0264
0.0008
0.2
0.05
0.002
0.25
0.0833
0.0039
0.3
0.1285
0.0069
0.35
0.1884
0.011
0.4
0.2666
0.0166
0.45
0.3681
0.0239
0.0019
0.5
0.5
0.0333
0.003
0.55
0.6722
0.0449
0.0043
0.6
0.9
0.0593
0.0061
0.65
1.2071...
Customers arrive at Rich Dunn's Styling Shop at a rate of 2 per hour, distributed in a Poisson fashion. Service times follow a negative exponential distribution, and Rich can perform an average of 5 haircuts per hour. customers (round your response to two decimal places). a) The average number of customers waiting for haircuts = customers (round your response to two decimal places). b) The average number of customers in the shop = c) The average time a customer waits...
arive at Rich Dunn's Styling Shop at a rate of 3 per hour, distibuted in a Poesson fashion Service times follow a negatve exponential average of 6 haircuts per hour a) The average number of customers waiting for harots-□ customers oound your response to Mo domal places b) The average number of customers in the shop customers (round your response to two decimal places) c) The average time a customer wats unts it is his or her turn minutes (round...
A shop has an average of five customers per hour
5. A shop has an average of five customers per hour (a) Assume that the time T between any two customers' arrivals is an exponential random variable. (b) Assume that the number of customers who arrive during a given time period is Poisson. What (c) Let Y, be exponential random variables modeling the time between the ith and i+1st c What is the probability that no customer arrives in the...
Calls arrive at Lynn Ann Fish's hotel switchboard at a rate of 1.5 per minute. The average time to handle each is 10 seconds. There is only one switchboard operator at the current time. The Poisson and negative exponential distributions appear to be relevant in this situation. a) The probability that the operator is busy = 0.25 (round your response to two decimal places). b) The average time that a caller must wait before reaching the operator = 0.06 minutes...
15 customers arrive every hour at Andy Johnson's food truck
when it parks outside the Orlando Courthouse from...
Table: Average Number of Customer in Waiting
Line
Poisson Arrivals, Exponential Service Times
Number of Service Channels, M
rhoρ
1
2
3
4
5
0.1
0.0111
0.15
0.0264
0.0008
0.2
0.05
0.002
0.25
0.0833
0.0039
0.3
0.1285
0.0069
0.35
0.1884
0.011
0.4
0.2666
0.0166
0.45
0.3681
0.0239
0.0019
0.5
0.5
0.0333
0.003
0.55
0.6722
0.0449
0.0043
0.6
0.9
0.0593
0.0061
0.65
1.2071...
Most questions answered within 3 hours.
-
Exercise 1. Two players, 1 and 2, take turns choosing numbers; 1
goes first. On his...
asked 5 minutes ago -
Are the following two functions overloaded?
int xyz(int x, int y = 100000);
int xyz(int x,...
asked 13 minutes ago -
An interest rate swap has three years of remaining life.
Payments are exchanged annually. Interest at...
asked 20 minutes ago -
Ensign Johnson is domiciled in Georgia. His wife is domiciled in
New York and moved to...
asked 17 minutes ago -
there are many issues that can be addressed when performing a
RCA. Assuming that there is...
asked 19 minutes ago -
ata pertaining to the postretirement health care benefit plan of
Danielson Delivery Service include the following...
asked 20 minutes ago -
Getting along with the members of your team requires good ____
skills.
a.
authoritative
b.
problem...
asked 28 minutes ago -
During June, Propene Company produced 20,000 chainsaw blades.
The standard quantity of material allowed per unit...
asked 34 minutes ago -
Draw the molecular orbital energy level diagrams and write the
electron configurations of (a) Be2, (b)...
asked 34 minutes ago -
We put a mixture of helium, oxygen and nitrogen gases in a
closed container at 25...
asked 44 minutes ago -
You measure 22 dogs' weights, and find they have a mean weight
of 64 ounces. Assume...
asked 52 minutes ago -
Complete and balance the following methesis reaction in aqueous
solution.
Instructions
• Use proper element capitalization....
asked 1 hour ago