Question

answer this please

Answer 1

Assume Are ideal then ab Diods Di Og Are in EB And shorter circuit. [forword Blas] 01 20 Wtu Modibied 2 - 2 2 foe 20 I Io f2 Apply Kul For All Loops Loop! 2 -20+ 2 [Jo- 1,]+2 [10712]=0; 20 = 410 - 2 I, + 2 I 2 - 0 Lool 2 [11+12] + 2 [0,- Io] 4 I, 7212 - 2 TO 0.>

Since 13-20. Loop 3 : 2 [7, +12 7+2 [1 7+30) = 0 Hizt 2 1+2 10 =0 Io = 26.6 By solving 1,2,3 equations I, a 23.3 I2=-20 So, As Ij = 23.3 Diode Di Forward bias Assumption correct, But D2 is Reverse bias Negitive. Da will opended , Agin Find I Now ov Im 20 2 2 I 20 T 2 [2112] 20 2a 20 Amp 3

e 103 جا کر NI From given N:N2 21시 N2 V : V2.23 vlt) Vm : 80 o sinot 5 16 Vm For RMS Vm 1) N - V2 N280 N2 니 Nm = 2oViv