Question

What volume (in L) of 0.300 M LiI will react with 0.150 L of a 0.175 M Pb(NO₃)₂ solution according to the following balanced chemical equation?

                        2LiI(aq)   +     Pb(NO₃)₂(aq)   

⟶⟶

⟶⟶ PbI₂(s)    +   2LiNO₃(aq)

Answer 1

What volume Cine) g 0.300 M Lil will geact with of 0.150 L to of 0.175 m Polresla solution according the following balanced chemical equation? 2 Li I caq) + Pb(NO3), (aq) pb Iz(s) + 2 Ling (aq) Above balanced chemical equation shows, 2 moles each mole need of li for each mole of pb anos/ Molority = No. og Moles Volume (in libres) M h - V X volume NO g moly Molority Pb (003/ .. calculate Moles of NO Moog moly Pb(NO3)₂ g E Molosity & volume 0.115 M Х 0.150 L Nood moles of Pb(NO3/= 0.02625 mol According to the Reaction reacts with role of g Molnas), two moles of li one mole

Therefore, 11 lir NO 2 x 0.0.2625 mol sig moles of = 0.0525 MOL No. og of moles en) Molowity Volume (in litres) м XV ท v x 0 : 300 M mol 0.0 525 mo smot S 0.0 525 mot 11 0.300 mot L 0.175 L V Lil volume of