Question

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Given the vectors u = (1, -2,1), v= {5,–4,0) and w = (3,0,-2) (6 points) a) Graph u, v, and was position vectors and label each vector. Show your calculation or justify your reasoning (4 points) b) To the nearest degree, what is the angle between the vectors u and w. (6 points) c) Write the equation of the plane containing the vectors u and w (4 points) d) Determine if the vectors u, v, and w are coplanar. Please label where one part begins *

Answer 1

W- [3,0,-2) solution! © U-<!-2017 The angle two vetors are tween Los e- lal 18/ -> Los (1,-2,1), ( 3,0,-2) Dit het . 1910th - 3 +0-2 6 113 1 Caso t 78 - () two is Velkrs U= 11, -2,13 W= 23,0,-2) The Equation of the plane containg P:fa.utb.ro ]. - (-2,0) 46(3,6.-2)] ſ a+ 36,-29, a-db} for the Equeation of the . plane in my z (n+36,-da, 9-2b) = (vy,z) raa=y Ja= - 1/2 forrpart a+36=2 => ab=a-a 36=x+ /2 b= anay 6 Scanned with CamScanner CS

Z-qe-o -***** )=z ya (29+y) - Z 3 -34-4X-dy. Z 6 -34-40-2y = 62 => 1 62 +4x+6y=0) .# c) = 24.-2,1), V= 25,-410) W=< 3,0-27 Giren vectors coplanas if bi bz bz are 3. C C C 1 -2 S -4 0 3 0 (8-0) + (-10-0) +1 (0+12) 8 -20 +12 20 d = 0 270 the reedor are coplansar CS Scanned with CamScanner