Question

What is the output of the following codes? Line1: public class ArrayCompare { Line2: public static void main (String[] args) { Line 3: int arrill {1, 2, 3}; Line 4: int arr2[1 {1, 2, 3}; Line5: if (arri == arr2) Line 6: System.out.println("Same"); Line: else Line 8: System.out.println("Not game"); Line9 : Line10:) حسین Same Not same

Answer 1

Solution :-

public class ArrComp
{
public static void main(String args[])
{
int arr1[] = {1,2,3};
int arr2[] = {1,2,3};
if(arr1 == arr2)
System.out.println("Same");
else
System.out.println("Not Same");
}

}

The output of the code is Not same.

Explanation :-

The output of the above code will be Not same. Although the elements in both the arrays is same i.e 1,2,3 but in this case when we compare both the arrays by using if decision statement i.e if(arr1 = = arr2), this will compare the base address of both the arrays. The arrays(arr1 and arr2) are stored in different memory locations and hence their base address will be different respectively.

Thus when the control of the program checks the condition if(arr1 = = arr2) it will be false and the control jumps to the else block and prints "Not same." Thus the output of the above code is Option b i.e Not same.